Enigma 1347: Fair and square
13 February 2014
Posted by on
From New Scientist #2506, 2nd July 2005
If you let A=1, B=2, C=3 etc then you can use these values to calculate the total score of any word. For example, ENIGMA has a score of 49. Interestingly SQUARE has a score which is square, PRIME has a score which is prime, ODD has a score which is odd, and EVEN has a score which is even.
I have now adjusted the values of some of the letters. For twenty-three letters their value is the same as before, but for the remaining three their values have been shuffled around. (For example I could have shuffled B, E and H to give B=8, E=2, H=5 with the other letters unchanged.) With these new values SQUARE has a different score from before but it is still square, PRIME has a lower score than before but it is still prime, ODD is still odd and EVEN is still even (but at least one of these last two words has a different score from before).
Which three letters have had their values changed, and what are their new values?