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The answer is apparent with a bit of analysis.

There are three different similar right-angled triangles. Each one has a side of length 10, labelling the smallest triangle (

o1,a1,h1) whereo1is the side opposite the smallest angle,a1is the side adjacent to it, andh1is the hypotenuse.The triangles (from smallest to largest) are thus:

The only triangle that can share non-integer sides with the other two is triangle 2, so this must be George's. And it must share

o2witha1(a1=o2=x) andh2witha3(h2=a3=y). The unshared sides beingo1andh3. So Fred's triangle is triangle 1 and George's triangle is triangle 3. And we need to compute (h3−o1).In triangle 2:

The following ratios are maintained:

In particular:

So the answer is:

Solution:Harry’s unmatched side is 10 cm longer than Fred’s unmatched side.The triangles look like this:

The 10 cm sides are shown in red. The lengths shared between Fred’s and George’s triangles are shown in green. The lengths shared between George’s and Harry’s triangles are shown in blue.

Where

x = √5 − 1, we can write the lengths of the triangles as follows:If we divide the lengths of the sides of the triangles by 10, so that each triangle has one side that is a unit length, then the length hypotenuse of Harry’s triangle is The Golden Ratio,

φ = (1 + √5)/2.The difference required in the answer is thus:

The smallest angle in the triangles is:

which is a solution of:

We can also let

SymPydo the maths for us.This Python program runs in 4.38s.

Great analysis, Jim.

So the five values are the geometric progression 10/φ, 10/√φ, 10, 10√φ, 10φ.

cos² α = tan² α = sin α = 1/φ = φ – 1.