Enigmatic Code

Programming Enigma Puzzles

Puzzle 42: Football – four teams

 From New Scientist #1093, 9th March 1978 [link]

Four football teams are to play each other once. After some of the matches had been played a table was drawn up giving some details of the matches played, won, lost, etc. But unfortunately Uncle Bungle had been at it again and the digits (from 0 to 9) had been replaced by letters. Each letter stood for the same digit wherever it appears and different letters stood for different digits.

The table looked like this:

(Two points are given for a win, and one point to each side in a drawn match).

Find the score in each match.


One response to “Puzzle 42: Football – four teams

  1. Jim Randell 8 August 2018 at 3:46 pm

    This Python program uses the [[ Football() ]] helper class from the enigma.py library. It runs in 163ms.

    Run: [ @repl.it ]

    from itertools import permutations
    from enigma import Football, irange, update
    # scoring system
    football = Football(points=dict(w=2, d=1))
    # labels for the teams
    (A, B, C, D) = (0, 1, 2, 3)
    # the table
    table = dict(played='pt??', w='???r', d='kp?k', points='???x')
    # allowable digits
    digits = set(irange(0, 9))
    # determine the outcomes in the matches
    for (ms, d) in football.substituted_table(table):
      # choose values for h and y
      for (h, y) in permutations(digits.difference(d.values()), 2):
        d1 = update(d, 'hy', (h, y))
        # look for scores in matches for A and C
        for ss in football.substituted_table_goals('h?ym', 'xhx?', ms, d=d1, teams=[A, C]):
          # calculate goals for/against B, D in matches except for B vs D
          (fB, aB) = football.goals([ss[(A, B)], ss[(B, C)]], [1, 0])
          (fD, aD) = football.goals([ss[(A, D)], ss[(C, D)]], [1, 1])
          # goals scored by D against B in the B vs D match
          DB = h - aB
          if DB < 0: continue
          m = fD + DB
          if m not in digits or m in d1.values(): continue
          # the goals scored by B against D in the B vs D match
          if ms[(B, D)] == 'l':
            BDs = irange(0, DB - 1)
            # we don't need further code here (although 'd' and 'x' can
            # easily be handled, 'w' would be more problematic)
            raise NotImplementedError()
          # output matches and possible scores
          for BD in BDs:
            football.output_matches(ms, update(ss, [((B, D), (BD, DB))]), teams="ABCD", d=update(d1, [('m', fD)]))

    Solution: The scores in the played matches are: A vs D = 5 – 6; B vs C = 4 – 4; B vs D = 0 – 1; C vs D = 0 – 2. The A vs B and A vs C matches are not yet played.

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