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Programming Enigma Puzzles

25 September 2017

Posted by on **From New Scientist #2252, 19th August 2000**

At snooker a player scores 1 point for potting one of the 15 red balls, but scores better for potting any of the 6 coloured balls: 2 points for yellow, 3 for green, 4 for brown, 5 for blue, 6 for pink, 7 for black.

Davies potted his first red ball, followed by his first coloured ball, then his second red ball followed by his second coloured ball, and so on until he had potted all 15 red balls, each followed by a coloured ball. Since the coloured balls are at this stage always put back on the table after being potted, it is possible to pot the same coloured ball repeatedly.

Davies’ break was interesting as after he had potted each of the 15 coloured balls his cumulative score called by the referee was always a prime number.

After potting the 15 red balls and 15 coloured balls, a player’s final task is to attempt to pot (in this order) yellow, green, brown, blue, pink and black. I won’t tell you how many of those Davies managed to pot, nor could you be sure how many of them he potted even if I told you his total score for the break.

What was that total score?

[enigma1096]

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4 September 2017

Posted by on **From New Scientist #2255, 9th September 2000** [link]

I have constructed a cyclical chain of four-digit perfect cubes such that each cube in the chain has no digits in common with either of its neighbours in the chain. The chain consists of as many different four-digit cubes as is possible, consistent with the stipulation that no cube appears in it more than once.

If I were to tell you how many cubes lie between 1000 and 1331 either by the shorter route or by the longer route round the chain you could deduce with certainty the complete order of the cubes in the chain.

Taking the longer route round the chain from 1000 to 1331, list in order the cubes that you meet (excluding 1000 and 1331).

[enigma1099]

31 July 2017

Posted by on **From New Scientist #2260, 14th October 2000** [link]

In the following statement digits have been consistently replaced by capital letters, different letters being used for different digits:

ONE and NINE are odd perfect squares, FOUR is an even perfect square.

Find the numerical value of the square root of (NINE × FOUR × ONE).

[enigma1104]

17 July 2017

Posted by on **From New Scientist #2262, 28th October 2000** [link]

Harry, Tom and I each found a set consisting of a 4-digit perfect square, a 3-digit perfect square and a 2-digit perfect square that between them used nine different digits; but none of us could add a 1-digit square with the unused digit because 9, 4, 1 and 0 all appeared in each of our three sets. No two of us found exactly the same set; none of the squares in my set appeared in either Harry’s set or Tom’s set. There is one further set that none of us found whose unused digit is again not itself a perfect square.

List in ascending order the three squares in this set that none of us found.

[enigma1106]

26 June 2017

Posted by on **From New Scientist #2265, 18th November 2000** [link]

At tennis a set is won by the first player to win 6 games, except that if the score goes to 5 games all, the set is won either by 7 games to 5 or by 7 games to 6. The first person to win three sets wins the match.

Sometimes at the end of a match each player has won exactly the same number of games. This happened when André beat Boris in a match in which no two sets contained the same number of games.

You will have to work out whether André won by 3 sets to 1 or by 3 sets to 2, but if I told you how many games in total each player won you would be able to deduce with certainty the score in each of the sets that André won and in the set or each of the sets that Boris won.

What was the score in each of the sets that André won? (Give each set’s score in the form

x-y, André’s score always comes first).

[enigma1109]

8 May 2017

Posted by on **From New Scientist #2272, 6th January 2001** [link]

Albion, Borough, City, Rangers and United played a tournament in which each team played each of the other teams once. Two matches took place in each of five weeks, each team having one week without a match.

One point was awarded for winning in the first week, 2 points for winning in the second week, 3 points for winning in the third week, 4 points for winning in the fourth week and 5 points for winning in the fifth week. For a drawn match each team gained half the points it would have gained for winning it. At any stage, teams that had gained the same number of points were regarded as tying.

After the first week A led, with B tying for second place. After the second week B led, with C tying for second place. After the third week C led, with R tying for second place. After the fourth week R led, with U tying for second place. After the fifth week U had won the tournament with more points than any of the other teams.

(1) Which team or teams finished in second place after the fifth week?

(2) Give the results of Albion’s matches, listing them in the order in which they were played and naming the opponents in each match.

This completes the archive of *Enigma* puzzles from 2001. There are now 1065 *Enigma* puzzles on the site, the archive is complete from the beginning of *Enigma* in February 1979 to January 1987, and from January 2001 to the final *Enigma* puzzle in December 2013. Altogether there are currently 59.5% of all *Enigmas* published available on the site, which leaves 726 *Enigmas* between 1987 and 2000 left to publish.

[enigma1116]

17 April 2017

Posted by on **From New Scientist #2275, 27th January 2001** [link]

I invite you to select a three-digit prime number such that if you reverse the order of its digits you form a larger three-digit prime number. Furthermore the first two digits and the last two digits of these two three-digit prime numbers must themselves be four two-digit prime numbers, each one different from all the others.

Which three-digit prime number should you select?

[enigma1119]

20 March 2017

Posted by on **From New Scientist #2279, 24th February 2001** [link]

In the following statement digits have been consistently replaced by capital letters, different letters being used for different digits:

VIER and NEUN are both perfect squares.

If I told you the number represented by VIER you could deduce with certainty the number represented by NEUN. Alternatively, if I told you the number represented by NEUN you could deduce with certainty the number represented by VIER.

What is the numerical value of the square root of (VIER × NEUN)?

[enigma1123]

6 February 2017

Posted by on **From New Scientist #2285, 7th April 2001** [link]

The coins from 1p to 100p in circulation are for 1p, 2p, 5p, 10p, 20p, 50p and 100p. If one receives 40p in change for a purchase it can be paid in a minimum of 2 coins (20p + 20p) but could be paid in one coin more than that minimum number (20p + 10p + 10p). But a few amounts of change cannot be paid for in one coin more than the minimum possible number of coins, for instance 1p and 50p.

Harry, Tom and I each paid 100p for an item priced such that the change due could not be paid in one coin more than the minimum possible number of coins. Each item cost a different amount.

Next day Harry and Tom bought the same items at the same price as on the previous day, whereas I bought a different item at a different price from any of the others, which again was such that the change due from 100p could not be paid in one coin more than the minimum possible number of coins. Each day the total cost of the three purchases was a prime number of pence.

How much did each of my purchases cost?

[enigma1129]

19 December 2016

Posted by on **From New Scientist #2292, 26th May 2001** [link]

Triangular numbers are those that fit the formula ½n(n+1), like 1, 3, 6 and 10.

In the following statement digits have been consistently replaced by capital letters, different letters being used for different digits:

“ONE, THREE, SIX and TEN are all triangular numbers, none of which starts with a zero”.

Which numbers are represented (in this order) by ONE, THREE, SIX and TEN?

[enigma1136]

14 November 2016

Posted by on **From New Scientist #2297, 30th June 2001** [link]

In the following statements digits have been consistently replaced by capital letters, different letters being used for different digits:

TWO is a prime number,

FOUR is a perfect square,

EIGHT is a [perfect] cube.You should assume that neither TWO nor FOUR nor EIGHT starts with a zero.

Find the number represented by EIGHT.

[enigma1141]

26 September 2016

Posted by on **From New Scientist #2304, 18th August 2001** [link]

After they had each played four rounds in the golf tournament Bernhard, Colin, Darren and Ernie all ended up with the same total score even though the scores for the 16 individual rounds that they played were all different. Each player’s score for each round was in the 60s or 70s (that is to say between 60 and 79 inclusive). Bernhard’s score in each of his four rounds was a prime number, Colin’s score in each of his four rounds was a semi-prime (the product of two prime numbers), Darren’s and Ernie’s scores in each of their four rounds were numbers that are neither prime nor semi-prime. Darren’s best (lowest) round was better than Ernie’s best round, and Darren’s worst round was better than Ernie’s worst round.

List in ascending order Ernie’s scores for the four rounds.

[enigma1148]

22 August 2016

Posted by on **From New Scientist #2309, 22nd September 2001** [link]

In the Fibonacci sequence the first two terms are 1 and 1, and each subsequent term is the sum of the previous two terms; so the sequence starts 1, 1, 2, 3, 5. Less well known is the Lucas sequence, whose first two terms are 1 and 3, and each subsequent term is the sum of the previous two terms; so the sequence starts 1, 3, 4, 7, 11. In the Tribonacci sequence (so named by Mark Feinberg) the first three terms are 1, 1 and 2, as in the Fibonacci sequence, and each subsequent term is the sum of the previous three terms; so it starts 1, 1, 2, 4, 7.

Harry, Tom and I were looking to find a 2-digit Fibonacci number, a 2-digit Lucas number and a 2-digit Tribonacci number that used six different digits. We each found a different solution; our three Fibonacci numbers were all different from each other; our three Lucas numbers were all different from each other; and our three Tribonacci numbers were all different from each other. None of the numbers in my solution appeared in either Harry’s or Tom’s solution.

List in ascending order the numbers in my solution.

[enigma1153]

25 July 2016

Posted by on **From New Scientist #2313, 20th October 2001** [link]

Albion, Borough, City, Rangers and United have played another tournament. This time each team played each of the other teams twice. The two matches that any two teams played against each other had different results, even in the case of City, which did not draw any of its matches.

Two points were awarded for a win and one point for a draw. After each team had played each of the other teams once, United was in the lead, one point ahead of Rangers, which was one point ahead of City, which was one point ahead of Borough, which was one point ahead of Albion.

But by the end of the tournament the positions were completely the opposite: Albion finished one point ahead of Borough, which was one point ahead of City, which was one point ahead of Rangers, which was one point ahead of United.

If you knew the results of the first match between Borough and United you could deduce with certainty the results of all the other matches played.

Give the result of the first match Borough played against each of the other four teams, naming the opponents in each match.

[enigma1157]

20 June 2016

Posted by on **From New Scientist #2318, 24th November 2001** [link]

Harry and Tom each chose a four-digit number that was either a perfect square or a triangular number and told me its last two digits. I deduced that Harry’s number was one of exactly two four-digit perfect squares or one of exactly two four-digit triangular numbers, but that Tom’s number was one of exactly three four-digit perfect squares or one of exactly three four-digit triangular numbers.

Then they told me that the sum of the digits of Harry’s number was the same as the sum of the digits of Tom’s number.

What were (a) Harry’s number and (b) Tom’s number?

[enigma1162]

13 May 2016

Posted by on **From New Scientist #1493, 30th January 1986** [link]

England, Scotland, Wales, Ireland and France took part in the Rugby union five-nations championship, each country playing each other country once. Two match points were awarded for a win and one match point for a draw, and the total number of match points gained by each country was: England 7, Scotland 6, Wales 4, Ireland 2, France 1.

No two matches had the same score and no country scored more than six points in any match; but each country scored exactly the same number of points in the championship as each other country, and Wales also had this number of points scored against them.

Those not familiar with the point scoring system of rugby union merely need to know that it is not possible for a side to score one, two or five points in a match.

What were the results and scores of Wales’s matches in the championship?

[enigma344]

10 May 2016

Posted by on **From New Scientist #2324, 5th January 2002** [link]

I have found a four-digit number such that it is impossible to factorise the numbers formed by its first digit or last digit or first two digits or middle two digits or last two digits or first three digits or last three digits or all four digits. In other words all those eight numbers are prime except that either or both of the single-digit numbers may be unity.

Harry and Tom have also each found such a four-digit number. The four-digit numbers that we have found are all different; but Harry’s number uses the same digits as Tom’s number, though in a different order.

Which four digit number have I found?

This completes the archive of puzzles from 2002.

[enigma1168]

18 April 2016

Posted by on **From New Scientist #2327, 26th January 2002** [link]

I drew an irregular hexagon. I also drew three straight lines, each of which ran from one angle of the hexagon to the next angle but two. Since the lines all intersected at the same point the hexagon was divided into six triangles. At the point of intersection each triangle had an angle of 60°.

All sides of all the triangles were an integral number (less than 50) of centimetres in length, and the six sides that met at the point of intersection (each one common to two triangles) all had different lengths.

What in centimetres was the perimeter of the hexagon?

[enigma1171]

21 March 2016

Posted by on **From New Scientist #2331, 23rd February 2002** [link]

UN,NEUFandCENTare all perfect squares.Find the numerical value of the square root of (

UN×NEUF×CENT).

For some reason this puzzle is labelled as **Enigma 1112** in the magazine.

This puzzle is somewhat similar to **Enigma 1291** (also set by Richard England).

[enigma1175]

29 February 2016

Posted by on **From New Scientist #2334, 16th March 2002** [link]

The teacher challenged the children to find a particular 5-digit number consisting of 5 different digits such that when they multiplied it by 2 they created another 5-digit number consisting of the other 5 digits.

By giving the children the last two digits of the number that they had to find the teacher ensured that there was only one possible answer; but I shall be less kind and merely tell you that the last digit of the number they had to find was 1.

What was that number ending in 1 that they had to find?

[enigma1178]

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