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If we consider the “difference of two squares” formula:
If y = 0 the result is x².
If y = 1 the result is x² − 1, so it is always smaller than the previous result.
And in general for y > 0 the result x² − y² is always less than x².
So, the answer to the last question is y**2.
@ruud: That’s right.
Here’s the ‘proof’:
Output: